suppose a simple random sample of size N equals 150 is obtained from a population who size is N equals 30,000 and who's
Posted: Sun Jul 10, 2022 10:49 am
suppose a simple random sample of size N equals 150 is obtained from a population who size is N equals 30,000 and who's population proportion with a specificed characteristic is P equals 0.6 complete parts a through c
Suppose a simple random sample of size n= 150 is obtained from a population whose size is N=30,000 and whose population proportion with a s
lation proportion with a specified characteristic is p=0.6. Complete parts (a) through (c) below.
(a) Describe the sampling distribution of p. Choose the phrase that best describes the shape of the sampling distribution below. OA. Not normal because n ≤0.05N and np(1-p) ≥ 10. OB. Approximately normal because n≤0.05N and np(1-p) ≥ 10. OC. Approximately normal because n≤0.05N and np(1-p) < 10. OD. Not normal because n ≤0.05N and np(1-p) < 10. Determine the mean of the sampling distribution of p. =(Round to one decimal place as needed.) HA = Determine the standard deviation of the sampling distribution of p. (Round to six decimal places as needed.) 0A = Р
(b) What is the probability of obtaining x = 93 or more individuals with the characteristic? That is, what is P(p ≥ 0.62)? P(p20.62) = (Round to four decimal places as needed.) (c) What is the probability of obtaining x=84 or fewér individuals with the characteristic? That is, what is P(p ≤0.56)? P(ps0.56)= (Round to four decimal places as needed.)
Suppose a simple random sample of size n= 150 is obtained from a population whose size is N=30,000 and whose population proportion with a s
lation proportion with a specified characteristic is p=0.6. Complete parts (a) through (c) below.
(a) Describe the sampling distribution of p. Choose the phrase that best describes the shape of the sampling distribution below. OA. Not normal because n ≤0.05N and np(1-p) ≥ 10. OB. Approximately normal because n≤0.05N and np(1-p) ≥ 10. OC. Approximately normal because n≤0.05N and np(1-p) < 10. OD. Not normal because n ≤0.05N and np(1-p) < 10. Determine the mean of the sampling distribution of p. =(Round to one decimal place as needed.) HA = Determine the standard deviation of the sampling distribution of p. (Round to six decimal places as needed.) 0A = Р
(b) What is the probability of obtaining x = 93 or more individuals with the characteristic? That is, what is P(p ≥ 0.62)? P(p20.62) = (Round to four decimal places as needed.) (c) What is the probability of obtaining x=84 or fewér individuals with the characteristic? That is, what is P(p ≤0.56)? P(ps0.56)= (Round to four decimal places as needed.)