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Posted: **Sun Jul 10, 2022 10:23 am**

: Let X Be A Normal Random Variable With Mean 30 And Standard Deviation 8 Find Its 90th Percentile I E Find A Number Y 1 (17.05 KiB) Viewed 90 times

Let X be a Normal random variable with mean 30 and standard deviation 8. Find its 90th percentile (i.e. find a number y such that P(X < y) = 0.9) (provide one digit to the right of decimal point)