1 x² + 4x + 8 dx 0³ 1 + sin 04 de ex 1 - tan ex dx 1 √ [1 + (In 1)²] dt
Posted: Sat Jul 09, 2022 3:34 pm
- 1 X 4x 8 Dx 0 1 Sin 04 De Ex 1 Tan Ex Dx 1 1 In 1 Dt 1 (55.47 KiB) Viewed 28 times
1 x² + 4x + 8 dx 0³ 1 + sin 04 de ex 1 - tan ex dx 1 √ [1 + (In 1)²] dt