Answer Happy • dy dx 3. xyy' = x² +1 5. (e" – 1)y′ = 2+c0$x 1. 7. 9. de dt dp dt = 3x²y² 1 sec 0 0e¹² = t²p - p + t² - 1

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dy dx 3. xyy' = x² +1 5. (e" – 1)y′ = 2+c0$x 1. 7. 9. de dt dp dt = 3x²y² 1 sec 0 0e¹² = t²p - p + t² - 1

Posted: Sat Jul 09, 2022 3:34 pm

by answerhappygod

: Dy Dx 3 Xyy X 1 5 E 1 Y 2 C0 X 1 7 9 De Dt Dp Dt 3x Y 1 Sec 0 0e T P P T 1 1 (26.88 KiB) Viewed 29 times

dy dx 3. xyy' = x² +1 5. (e" – 1)y′ = 2+c0$x 1. 7. 9. de dt dp dt = 3x²y² 1 sec 0 0e¹² = t²p - p + t² - 1