Consider applying the Lagrange Multipliers method: Vf = (2x, 1), AVg = (2x, 2λy). So 2x = 2x This is elementary algebra.
Posted: Sat Jul 09, 2022 2:25 pm
Consider applying the Lagrange Multipliers method: Vf = (2x, 1), AVg = (2x, 2λy). So 2x = 2x This is elementary algebra. What are the possible values for lambda and x