Answer Happy

Object Height. Suppose an object is thrown straight up from the ground. The height after t seconds is given by the formula +73+²+ 182 h(t) = -4t³ (a) The time in seconds when the object reached the highest point was Note: Round to 4 digits after the decimal point, if rounding is required 12.1667 s 182 s Os O None of the other answers 9.125 s 27.375 s (b) The height is maximized at the critical point x = a because the second derivative test found f"(a) = 0 f'(a) = 0 O f'(a) was positive to the left of x = a and negative to the right f"(a) < 0 f"(a) > 0 Of'(a) was negative to the left of x = a and positive to the right