(1 point) Given the curve R(t) = 2ti + 5t²j + 3t³ k (1) Find R' (t) (2) Find R" (t) (3) Find the curvature = (sqrt(1800t
Posted: Sat Jul 09, 2022 2:15 pm
(1 point) Given the curve R(t) = 2ti + 5t²j + 3t³ k (1) Find R' (t) (2) Find R" (t) (3) Find the curvature = (sqrt(1800t^4+1296t^2+400))/(81t^4+100t^2+4)^(3/2) = 2i + 10tj+9t^2k 10j+18tk