Page 1 of 1

Find f'(x) = 2 cos(x) + sec²(x), -a/2
Posted: Sat Jul 09, 2022 2:15 pm
by answerhappygod
 1
1 (7.01 KiB) Viewed 28 times
Find f'(x) = 2 cos(x) + sec²(x), -a/2<x< л/2, and f(x/3) = -5. f(x) =