A ball is thrown vertically upward with an initial velocity of 48 feet per second. The distances (in feet) of the ball f
Posted: Sat Jul 09, 2022 2:06 pm
A ball is thrown vertically upward with an initial velocity of 48 feet per second. The distances (in feet) of the ball from the ground after t seconds is s = 48t - 16t². (a) At what time t will the ball strike the ground? (b) For what time t is the ball more than 20 feet above the ground? (a) The ball will strike the ground when t is seconds. (b) The ball is more than 20 feet above the ground for the time t when (Simplify your answer.) <t< s=48t-16t² 20 ft