Answer Happy • In the titration of acetic acid (Mm = 60.1 g/mol) in a 5.00 mL sample of vinegar (d = 1.01 g/mL), 10.25 mL of 0.501 M Na

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In the titration of acetic acid (Mm = 60.1 g/mol) in a 5.00 mL sample of vinegar (d = 1.01 g/mL), 10.25 mL of 0.501 M Na

Posted: Sat Jul 09, 2022 12:29 pm

by answerhappygod

In the titration of acetic acid (Mm = 60.1 g/mol) in a 5.00 mL sample of vinegar (d = 1.01 g/mL), 10.25 mL of 0.501 M NaOH were consumed. Determine the molar concentration of acetic acid in the vinegar.