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Two 12.6cm diameter electrodes 0.591cm apart form a parallel plate capacitor. The electrodes are attached by metal wires

Posted: Sat Jul 09, 2022 12:20 pm
by answerhappygod
Two 12 6cm Diameter Electrodes 0 591cm Apart Form A Parallel Plate Capacitor The Electrodes Are Attached By Metal Wires 1
Two 12 6cm Diameter Electrodes 0 591cm Apart Form A Parallel Plate Capacitor The Electrodes Are Attached By Metal Wires 1 (217.03 KiB) Viewed 32 times
Two 12.6cm diameter electrodes 0.591cm apart form a parallel plate capacitor. The electrodes are attached by metal wires to the terminals of a 16.9V battery. What are the magnitude of charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes while the capacitor is attached to the battery? (Enter the magnitude of the charges first, then the electric field strength, and the potential difference last.) 3.16x10-10 C You are correct. Your receipt no. is 156-1221 Previous Tries 2.86x10³ N/C You are correct. Your receipt no. is 156-580 1.69x 10¹ V You are correct. Your receipt no. is 156-8298 Previous Tries What are the magnitude of charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes after insulating handles are used pull the electrodes away from each other until they are 1.17cm apart? The electrodes remain connected to the battery during this process. (Enter the magnitude of the charges first, then the electric field strength, and the potential difference last.) 8.16 10^-10 C Submit Answer Incorrect. Tries 1/10 Previous Tries 0.714KV Submit Answer 4.22V Submit Answer Submit Answer Incorrect. Tries 1/10 Previous Tries What are the magnitude of charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes after the original electrodes (moved back to 0.591cm apart) are expanded until they are 25.6cm in diameter while remaining connected to the battery? (Enter the magnitude of the charges first, then the electric field strength, and the potential difference last.) Submit Answer Submit Answer Submit All Unable to interpret units. Computer reads units as "KV". Tries 0/10 Previous Tries Previous Tries Tries 0/10 Tries 0/10 Tries 0/10