Answer Happy

Part 2 please! if you can show your work it will help a lot. Igot my data but I don't know what to do in part 2.
Lab: Torque and Equilibrium The purpose of this experiment is to verify the principle of balanced torques for a rigid body in equilibrium. The "rigid" body is a meter stick suspended in horizontal equilibrium from a lab stand by a knife-edge clamp. Slotted masses are suspended from the stick by knife-edge clamps and 50-g mass hangers. DATA ACQUISTION Find the mass of the meter stick with a balance. Slide the supporting clamp until the stick is horizontal. The center of gravity is then located below the knife-edge. Mass of stick: m = ___107.5____ g. Center of gravity of stick: x = _51.3___ cm. Bring the stick into horizontal equilibrium for each case in the data tables. Let x, be the location of the stick's suspension clamp. Masses m₁, m2, and m; are hung from the stick at X₁, X₂, and x₁, respectively. (Each mass includes clamp, hanger, and slotted masses.) In Cases 1-3 the stick is suspended at its center of gravity (x₁=x-). In Cases 4-6 the stick's suspension clamp is moved to (x-?) achieve horizontal equilibrium. Stick Suspended at Center of Gravity m₁ (g) x₁ (cm) m₂ (g) x₂ (cm) m; (g) 10.0 120 100 100 10.0 120 100 10.0 120 Cas e 1 2 3 Cas e 4 5 6 100 100 100 30.0 40.0 60.0 Stick Not Suspended at Center of Gravity m₁ (g) x₁ (cm) m₂ (g) x₂ (cm) xo (cm) 5.0 5.0 5.0 160 160 160 160 60.0 160 90.0 X3 (cm) 94.1 85.9 70.4 28.9 42.3 55.4
PART 1 Calculate the torques around the point x, to verify that ther-0. The unmeasured force Fo exerts a zero torque around xo. The weight of the stick Facts at the center of gravity of the stick. In Cases 1-3, x, and x, are the same so that F. exerts a zero torque around xo- In Cases 4-6, xo and x are different so that F exerts a nonzero torque around xo. Calculate Tew and Tew in units of mN. Don't forget the conversions for length and mass. The net torque Tnet-Tecw+Tew should be zero, but that may be nonzero because of small errors. The % error is given by [Tnet/Tccw]x100%. Round off the % error to two digits. Case 1 2 3 4 5 6 PART 1: Torques (mN) around x-xo Toow 0.0669 0.0549 0.0413 0.0239 0.0373 0.0548 Tew 0.0685 0.0554 0.0410 0.0241 0.0380 0.0554 Thet -0.0016 -0.0005 0.0003 -0.0002 -0.0007 -0.0006 % Error 2.4 0.9 0.7 0.8 1.9 1.0
PART 2 Although Fo is not measured, it can be calculated from the data by means of the rotational and translational equilibrium conditions. Calculate torques around the point x=0. The only CCW torque on the stick is exerted by Fo. The rotational equilibrium condition states that xoFo+0. Hence, Fo=/xo. The lever arms for the CW torques are x₁, X2, X3, and x. Let's call this result ROT Fo The translational equilibrium condition states that Fo+F₁+F₂+F₁+F=0. In terms of the absolute magnitudes of the forces Fo=F₁+F₂+F3+Fc. Let's call this result TRAN Fo. Although the above calculations of Fo should agree, they may differ because of small errors. The % error is given by [ROT F-TRAN F₁\/TRAN Fo]x100%. Round off the % error to two digits. Case 1 2 3 4 5 6 PART 2: CW Torque (mN) around x=0 and F, (N) ROT Fo - ten o TRAN Fo F₁+F₂+F+F Tew % Error