The position vector of a particle of mass 2.10 kg as a function of time is given by r = (6.00 i + 5.90 tj), where is in
Posted: Sat Jul 09, 2022 12:06 pm
The position vector of a particle of mass 2.10 kg as a function of time is given by r = (6.00 i + 5.90 tj), where is in meters and t is in seconds. Determine the angular momentum of the particle about the origin as a function of time. k) kg. m²/s