Two 12.6cm diameter electrodes 0.591cm apart form a parallel plate capacitor. The electrodes are attached by metal wires

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Two 12.6cm diameter electrodes 0.591cm apart form a parallel plate capacitor. The electrodes are attached by metal wires

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Two 12 6cm Diameter Electrodes 0 591cm Apart Form A Parallel Plate Capacitor The Electrodes Are Attached By Metal Wires 1
Two 12 6cm Diameter Electrodes 0 591cm Apart Form A Parallel Plate Capacitor The Electrodes Are Attached By Metal Wires 1 (82.11 KiB) Viewed 50 times
Two 12.6cm diameter electrodes 0.591cm apart form a parallel plate capacitor. The electrodes are attached by metal wires to the terminals of a 16.9V battery. What are the magnitude of charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes while the capacitor is attached to the battery? (Enter the magnitude of the charges first, then the electric field strength, and the potential difference last.) 3.16x10-10 C Previous Tries You are correct. Your receipt no. is 156-1221 2.86x10³ N/C You are correct. Your receipt no. is 156-580 1.69x 10¹ V You are correct. Your receipt no. is 156-8298 → Previous Tries What are the magnitude of charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes after insulating handles are used to pull the electrodes away from each other until they are 1.17cm apart? The electrodes remain connected to the battery during this process. (Enter the magnitude of the charges first, then the electric field strength, and the potential difference last.) Submit Answer 0.714KV Submit Answer 4.22V Submit Answer Incorrect. Tries 1/10 Previous Tries Submit Answer Incorrect. Tries 1/10 Previous Tries What are the magnitude of charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes after the original electrodes (moved back to 0.591cm apart) are expanded until they are 25.6cm in diameter while remaining connected to the battery? (Enter the magnitude of the charges first, then the electric field strength, and the potential difference last.) Submit Answer Tries 0/10 Submit Answer Previous Tries Unable to interpret units. Computer reads units as "KV". Tries 0/10 Previous Tries Tries 0/10 Tries 0/10
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