Learning Goal: Two Lenses in Combination - you will solve the problem step by step to find the final image. Pay attentio
Posted: Sat Jul 09, 2022 11:59 am
The focal length of the diverging lens is f1 =-17.0 cm. The focal length of the converging lens is f2 = 30.0 cm. The distance between the two lenses is D= 56.0 cm. An object is placed 10.20 cm to the Left of the Diverging lens. Its height is 15.0 cm. ▸ Part A-Lens 1- the Diverging lens: find the image distance d₁₁ of the first image with a proper sign. ▸ Part B-Lens 1-the Diverging lens: find the image height h₁, of the first image with a proper sign. Part C-Lens 1-the Diverging lens: what is the type of the first image, and on which side of Lens 1 is the first image located? First image Bubmit is Virtual, and is located to the Left side of Lens 1 is Real, and is located to the Right side of Lens 1 Previous Answers Correct
Now make the transition from Lens 1 to Lens 2. The first image is the OBJECT for lens 2. The distance between the two lenses is D= 56.0 cm. The focal length of the Converging lens is f2 = 30.0 cm. ▶ Part D-Lens 2-the Converging lens: what is the OBJECT distance dog with a proper sign? ▸ Part E-Lens 2-the Converging lens: find the image distance dia of the second (final) image with a proper sign. ▸ Part F-Lens 2-the Converging lens: find the image height hip of the second (final) image with a proper sign. Part G-Lens 2-the Converging lens: what is the type of the second (final) image, and on which side of Lens 2 is the second (final) image located? Second (final) image SUOM is Virtual, and is located to the Loft side of Lens 2 is Real, and is located to the Right side of Lens 2 Previous Answers