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Posted: **Sat Jul 09, 2022 11:59 am**

: Learning Goal Two Lenses In Combination You Will Solve The Problem Step By Step To Find The Final Image Pay Attentio 1 (61.61 KiB) Viewed 42 times

: Learning Goal Two Lenses In Combination You Will Solve The Problem Step By Step To Find The Final Image Pay Attentio 2 (33.9 KiB) Viewed 42 times

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: Learning Goal Two Lenses In Combination You Will Solve The Problem Step By Step To Find The Final Image Pay Attentio 4 (33.14 KiB) Viewed 42 times

Learning Goal: Two Lenses in Combination - you will solve the problem step by step to find the final image. Pay attention to the SIGN Convention. The sign of each quantity has meaning. As shown in Lenses in Combination 1 Corging lens Diverging lens a converging thin lens with focal points indicated by F₁'s is placed to the left of a diverging thin lens with focal points indicated by F2's. The focal length of the converging lens is f1 = 16.0 cm. The focal length of the diverging lens is f2 = -28.0 cm. The distance between the two lenses is D = 56.0 cm. An object is placed 35.20 cm to the Left of the Converging lens. Its height is 15.0 cm
The focal length of the converging lens is f₁ = 16.0 cm. The focal length of the diverging lens is f2 = -28.0 cm. The distance between the two lenses is D= 56.0 cm. An object is placed 35.20 cm to the Left of the Converging lens. Its height is 15.0 cm. ▸ Part A-Lens 1- the Converging lens: find the image distance d₁, of the first image with a proper sign. ▸ Part B - Lens 1- the Converging lens: find the image height hy of the first image with a proper sign. Part C-Lens 1-the Converging lens: what is the type of the first image, and on which side of Lens 1 is the first image located? First image Subit is Virtual, and is located to the Left side of Lens 1 is Real, and is located to the Right side of Lens 1 Previous Answers Correct
The focal length of the converging lens is f₁ = 16.0 cm. The focal length of the diverging lens is f2 = -28.0 cm. The distance between the two lenses is D= 56.0 cm. An object is placed 35.20 cm to the Left of the Converging lens. Its height is 15.0 cm. ▸ Part A-Lens 1- the Converging lens: find the image distance d₁, of the first image with a proper sign. ▸ Part B - Lens 1- the Converging lens: find the image height hy of the first image with a proper sign. Part C-Lens 1-the Converging lens: what is the type of the first image, and on which side of Lens 1 is the first image located? First image Subit is Virtual, and is located to the Left side of Lens 1 is Real, and is located to the Right side of Lens 1 Previous Answers Correct
Now make the transition from Lens 1 to Lens 2. The first image is the OBJECT for lens 2. The distance between the two lenses is D= 56.0 cm. The focal length of the diverging lens is f2 = -28.0 cm. ▸ Part D-Lens 2-the Diverging lens: what is the OBJECT distance do2 with a proper sign? ▸ Part E-Lens 2-the Diverging lens: find the image distance dia of the second (final) image with a proper sign. ▸ Part F-Lens 2-the Diverging lens: find the image height hip of the second (final) image with a proper sign. Part G-Lens 2-the Diverging lens: what is the type of the second (final) image, and on which side of Lens 2 is the second (final) image located? Second (final) image is Virtual, and is located to the Left side of Lens 2 is Real, and is located to the Right side of Lens 2 Previous Answers ✓ Correct