-> = -> A | B | C | D -> + | * | () | Using the prov
Posted: Fri Jul 08, 2022 6:40 am
<assign> -> <id> =<expr>
<id> -> A | B | C | D
<expr> -> <id> + <expr> |<id> * <expr> | (<expr>) |<id>
Using the provided grammar, show the parse treeand leftmost derivation for the following twoexpression:
A = A * ( B + ( C * A ) )
B = A * B + C * D
<id> -> A | B | C | D
<expr> -> <id> + <expr> |<id> * <expr> | (<expr>) |<id>
Using the provided grammar, show the parse treeand leftmost derivation for the following twoexpression:
A = A * ( B + ( C * A ) )
B = A * B + C * D