-> = -> A | B | C | D -> + | * | () | Using the prov
Posted: Fri Jul 08, 2022 6:40 am
<assign> -><id> = <expr>
<id> -> A | B | C |D
<expr> -> <id>+ <expr> | <id> * <expr> | (<expr>) |<id>
Using the provided grammar, show theparse tree and leftmostderivation for the following two expression:
A = A * ( B + ( C * A ))
B = A * B + C * D
<id> -> A | B | C |D
<expr> -> <id>+ <expr> | <id> * <expr> | (<expr>) |<id>
Using the provided grammar, show theparse tree and leftmostderivation for the following two expression:
A = A * ( B + ( C * A ))
B = A * B + C * D