fun f (d, e, g, h) The abstract syntax tree off is the following: / / f(d, e, g, h) d apply. = h[d(e, g)] + g[e[0]] + "b
Posted: Fri Jul 08, 2022 6:38 am
- Fun F D E G H The Abstract Syntax Tree Off Is The Following F D E G H D Apply H D E G G E 0 B 1 (25.79 KiB) Viewed 42 times
fun f (d, e, g, h) The abstract syntax tree off is the following: / / f(d, e, g, h) d apply. = h[d(e, g)] + g[e[0]] + "bar" "bar" Fill in the blank, reducing all types to basic types and type constructors if possible: Type of d = Type of e Type of g Type of h Type that freturns-