A 480/0⁰ VAC wye-connected generator supplies a balanced delta-connected load. Load impedance is 15 + j10 Ω per phase, l
Posted: Fri Jul 08, 2022 6:27 am
A 480/0⁰ VAC wye-connected generator supplies a balanceddelta-connected load. Load impedance is 15 + j10 Ω perphase, line impedance is 1 + j2 Ω per line, calculate thecurrent in the phase of the load. [Converting the delta load to anequivalent wye load with no neutral connection, the phase impedanceof the equivalent wye load is 1/3 the phase impedance of the deltaload as in Problem 1c., above. The equivalent phase voltage in theload is 480/√3/-30⁰ . Then
Iphase =Vphase/(Zphase+ Zline) = 34.5/-71.6⁰ A
An ammeter in one of the phases of the delta connected loadreads 34.5 A. The problem can also be solved using the relationsbetween line and phase currents.]
Wye connected voltage sources that supply delta connected loadsare most common.
Iphase =Vphase/(Zphase+ Zline) = 34.5/-71.6⁰ A
An ammeter in one of the phases of the delta connected loadreads 34.5 A. The problem can also be solved using the relationsbetween line and phase currents.]
Wye connected voltage sources that supply delta connected loadsare most common.