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Figure 1.1 and Figure 1.2 illustrate a single-phase full wave rectifier circuit feeding a resistive-inductive load and chart determining the extinction angle d'e respectively. Vs = 120Vrms at 50 Hz, α = 40°, RLd = 12N, LLd = 50mH Single-phase ac supply de (electrical degrees) 360 340 320 300 280 260 240 220 200 180 Figure 1.1 Single-phase full-wave controlled rectifier 0 cos = 0 cos = 0.2 cos = 0.4 cos = 0.6 cos = 0.8 cos = 0.9 ееееееееееее Cos = 1.0 20 40 v=Vm sincot Th 60 80 Th4 G1 O iG4 Th₂/ The C İG2 ¡G3 C n=21 D (α = α), Rid 100 120 140 a' (electrical degrees) n=3 (9/2-20 = 20) 160 A ellem I B n=6 (α = α-/12) Vid 180
a) b) d) (KNR 3243 POWER ELECTRONICS) Calculate the value of cos (p) for this circuit From Figure 1.2, approximate the extinction angle d'ext [3 Marks] From the previous questions, justify the mode of conduction (continuous or discontinuous) Sketch the voltage across a thyristor and the current through it [2 marks] Calculate the output voltage average [2 marks] [4 Marks] [4 Marks]