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Electrical Machines problem - Electricalengineering
please show your calculation,if calculation are notprovided, I will dislike and report if you do this.
1.1 If the number of turns of a coil wound over a core is halved, the inductance of the coil will become: ..... a. doubled b. halved c. quadrapuled th e. none of the above 1.2 Eddy current losses can be reduced by ..... a. using high quality magnetic material. using thin magnetic material. none of the above e. 1.3 A ferromagnetic ring with a mean circumference L-36 cm and a cross-sectional area A- 3 cm² is wound with 400 turns of wire as shown in Fig. 1. When the excitation current is 1.4 A, the flux is found to be = 1.4 mWb. The relative permeability of the iron 4, is .... a. 238732 b. 0.2387 2387 d. 238.7 1.4 A cast steel ring, as shown in Fig. 2 with B-H data as shown in Table 1, has a mean length of L-30 cm and an air gap of L-2 mm length. The number of ampere-turns (N) required to produce a flux density B = 0.6 T in the air gap is ... c. using light weigh magnetic material. d. using heavy weigh magnetic material. NI=1084 At. c. NI- 129 At. e. none of the above NI = 955 At. d. NI=0.86 At. O Fig. 1 Fig. 2 e. none of the above 1.5 The solenoid shown in the Fig. 3 consists of a 500 turn coil on a uniformly sized core. The core has a cross-sectional area 4,4 cm³. The length of the air gap is 1,5 mm long. is negligible and the coil exciting current /= 10 A, the total magnetic flux ..... mWb. If the reluctance of the core that circulates in the core is a. = 1.25 -0.50 c. $=5 d. = 12.5 e. none of the above 1.6 For the magnetic circuit shown in Fig. 4, the reluctance Res of the central limb (PS) is 10×105 AT/Wb and the reluctances Rers and Regs of the outer limbs (PTS and PQS) are same and equal to 15x10³ AT/Wb. To produce 0.5 mWb in PQS, the mmf to be produced by the coil is: a. 750 AT b. 250 AT c. 1500 AT 1750 AT e. none of the above Fig.3 Table 1: B-H data for Cast Steel 0.4 0.6 0.8 430 720 B(T) H(AU/m) 130 Fig. 4
DON'T COPY OTHER PEOPLE'S ANSWER HERE IN answers solve it all in clear and detailed Electrical Machines problem - Electric
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