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2sin ²4 √TZ 1≤r≤ 2,0 = 200%-2 ≤z≤ 3 (b) B= F-rzsin o cos + cos 20 r2² 2.

Posted: Fri Jul 08, 2022 6:20 am
by answerhappygod
2sin 4 Tz 1 R 2 0 200 2 Z 3 B B F Rzsin O Cos Cos 20 R2 2 1
2sin 4 Tz 1 R 2 0 200 2 Z 3 B B F Rzsin O Cos Cos 20 R2 2 1 (3.68 KiB) Viewed 40 times
2sin ²4 √TZ 1≤r≤ 2,0 = 200%-2 ≤z≤ 3 (b) B= F-rzsin o cos + cos 20 r2² 2.