There is an equimolar mixture of species 1 and 2 at a constant temperature of 90oC at very low pressure. The vapor press
Posted: Fri Jul 08, 2022 6:08 am
There is an equimolar mixture of species 1 and 2 at a constanttemperature of 90oC atvery low pressure. The vapor pressure of the components can bedetermined by the following equation:
log10 Pisat= Ai - (Bi/T)
For component 1: A1= 4.5 and B1= 1400For component 2: A2= 6.0 and B2= 1600The saturation pressure (Pisat) is in bar,and the temperature (T) is in K.The activity coefficients (γ) for the components are expressed asfollows:
For Component 1: ln γ1 = 0.8 x22For Component 2: ln γ2 = 0.8 x12
(a) At what pressure does the first bubble of vapor formand what is its composition at T= 90oC?
(b) Obtain the fugacity and activity of component 1 in theliquid phase at the bubble point condition.
(c) If this mixture forms an azeotrope at T=90oC, determine the composition and pressure of themixture atthe azeotrope point.
log10 Pisat= Ai - (Bi/T)
For component 1: A1= 4.5 and B1= 1400For component 2: A2= 6.0 and B2= 1600The saturation pressure (Pisat) is in bar,and the temperature (T) is in K.The activity coefficients (γ) for the components are expressed asfollows:
For Component 1: ln γ1 = 0.8 x22For Component 2: ln γ2 = 0.8 x12
(a) At what pressure does the first bubble of vapor formand what is its composition at T= 90oC?
(b) Obtain the fugacity and activity of component 1 in theliquid phase at the bubble point condition.
(c) If this mixture forms an azeotrope at T=90oC, determine the composition and pressure of themixture atthe azeotrope point.