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How far below the bridge, d, will the jumper eventually be hanging, once the jumper stops oscillating and comes finally to rest? Assume that the jumper does not touch the water. Express your answer in terms of m, L, g, and k. d= V ΑΣΦ | | | vec | Submit Request Answer Part B Complete previous part(s) Provide Feedback ? Next >
Learning Goal: To apply Newton's second law and the theorem of conservation of energy to solve kinetic problems. A bungee jumper wants to jump off the edge of a bridge that spans a river below. The jumper has a mass m, and the surface of the bridge is a height h above the water. The bungee cord, which has length L when un unntretched, will first straighten and then stretch as the jumper falls. Assume the following: • The bungee cord behaves as an ideal spring once it begins to stretch and has spring constant k • The jumper does not actually jump but simply steps off the edge of the bridge and falls straight downward. • The jumper's height is negligible compared to the length of the bungee cord. Thus, the jumper can be treated as a point particle. Use g for the magnitude of the acceleration due to gravity. CARINA Phonetiks PELICTANTE