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For the curved beam shown (hook with a total lifting capacity of m= 68 tonnes [1 tonne=1000 kg]): NOTE: Be sure to convert mass (m) to force (P) using the acceleration of gravity (g=9.816 m/s² such that P=mg r₁=200 mm |M=P*r, (where r = 5+¹)! y=- where r=- W In m=68 tonnes a) Use the curved beam equations to solve for the maximum, tensile bending stress at section A-A. My Note that = but max tensile stress is at the inner radius, . For this case & max tension Ae(r-y) M=P*r where r (=5+5). 3 W= 600 mm bh³ 12 b) Use the straight beam equation to solve for the maximum tensile bending stress at A-A. My Note that o straight = but maximum tensile stress is at the inner radius, I. For this case & max tension I tw³ = y=- and I= 12 t=150 mm and Awt (rectangular cross section), e = - -(rectangular cross section) c) Quantify the difference between the answers from a) and b) [Indicate which is "correct" at A-A] Comment on the correctness of either a) or b) for this case and why.