Use the limit comparison test to determine if the series converges or diverges. 00 9√√n Σ 5n3/2+4n-1 n=1 A) Diverges Det
Posted: Thu Jul 07, 2022 2:27 pm
by answerhappygod
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Use the limit comparison test to determine if the series converges or diverges. 00 9√√n Σ 5n3/2+4n-1 n=1 A) Diverges Determine convergence or divergence of the alternating series. (-2) 45. +5n 00 Σ n=1 B) Converges A) Converges B) Diverges