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Need a equation of f1, f2, f3
b. Recall that f(x) = 2x-1-1. Graph of f₁(x) = f(-x)+2, f₂(x) = f(-x + 1) + 1, and f3(x) = f1(x) + f₂ (x) are shown below. Label graph below f1, f2 and f3 In the space provided simply f1, f2 and f3 into the form fi = A(2)-(x+¹) + d. Hint to help correct the exponent in f₂ multiply the equation by 2/2: = (2) (¹) = (2)(2-¹) 1