For numbers a, b > 1, the expression loga(a²b5) + logb(a/b) can be simplified to A*loga(b) + B*logb(a) + C for some numb
Posted: Thu Jul 07, 2022 2:26 pm
For numbers a, b > 1, the expression loga(a²b5) + logb(a/b) can be simplified to A*loga(b) + B*logb(a) + C for some numbers A, B, C. What is A+B+C?