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It is easy to check that for any value of c, the function is solution of equation y(x) C = ce Find the value of c for which the solution satisfies the initial condition y(1) = 10. -2x te y + 2y=e=¹.
The solution of a certain differential equation is of the form y(t) = a exp(2t) + bexp(5t), where a and b are constants. The solution has initial conditions y(0) = 1 and y'(0) = 1. Find the solution by using the initial conditions to get linear equations for a and b. y(t)