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The position of an object that is oscillating on an ideal spring is given by the equation x = (12.3 cm) cos[(1.26s¯¹)t].
Posted: Thu Jul 07, 2022 2:14 pm
by answerhappygod
- The Position Of An Object That Is Oscillating On An Ideal Spring Is Given By The Equation X 12 3 Cm Cos 1 26s T 1 (71.06 KiB) Viewed 77 times
The position of an object that is oscillating on an ideal spring is given by the equation x = (12.3 cm) cos[(1.26s¯¹)t]. (a) At time t = 0.815 s, how fast is the object moving? ΠΙΑΣΦ Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B cm/s (b) At time t = 0.815 s, what is the magnitude of the acceleration of the object? ΨΠ ΑΣΦ cm/s²