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In the circuit of Figure, the equivalent capacitance is C₂ = 1.00 μF- O 5.0 μF O 1.20 μF O 0.8 μF O 2.67 µF C₁ = 2.00 μF
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In the circuit of Figure, the equivalent capacitance is C₂ = 1.00 μF- O 5.0 μF O 1.20 μF O 0.8 μF O 2.67 µF C₁ = 2.00 μF
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Thu Jul 07, 2022 2:13 pm
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answerhappygod
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In the circuit of Figure, the equivalent capacitance is C₂ = 1.00 μF- O 5.0 μF O 1.20 μF O 0.8 μF O 2.67 µF C₁ = 2.00 μF C₁ = 2.00 uF