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A proton in a synchrotron is moving in a circle of radius 1 km and increasing its speed by v(t) = C₁ + c₂t² , where C₁ =
Posted: Thu Jul 07, 2022 2:10 pm
by answerhappygod

- A Proton In A Synchrotron Is Moving In A Circle Of Radius 1 Km And Increasing Its Speed By V T C C T Where C 1 (23.6 KiB) Viewed 45 times

- A Proton In A Synchrotron Is Moving In A Circle Of Radius 1 Km And Increasing Its Speed By V T C C T Where C 2 (12.68 KiB) Viewed 45 times

- A Proton In A Synchrotron Is Moving In A Circle Of Radius 1 Km And Increasing Its Speed By V T C C T Where C 3 (11.11 KiB) Viewed 45 times
A proton in a synchrotron is moving in a circle of radius 1 km and increasing its speed by v(t) = C₁ + c₂t² , where C₁ = 1.6 × 105 m/s and C₂ = 105 m/s³. a. What is the proton's total acceleration at t = 5.0 s? a = x 10⁹ m/s² b. At what time does the expression for the velocity become unphysical? t = S
The total acceleration in this case is the magnitude of the acceleration vector which has two perpendicular components: centripetal and tangential. Hint 1 Hint 2
A good starting point for an unphysical velocity is the ultimate speed limit in the Universe. What is this speed limit? Hint 2