A 1.9-MeV (kinetic energy) proton enters a 0.25-T field, in a plane perpendicular to the field.
Posted: Thu Jul 07, 2022 2:08 pm
Question: what is the radius of its path?
A 1.9-MeV (kinetic energy) proton enters a 0.25-T field, in a plane perpendicular to the field.
A 1.9-MeV (kinetic energy) proton enters a 0.25-T field, in a plane perpendicular to the field.