Answer Happy

(14%) Problem 6: A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the block. The bullet's mass is m=0.0095 kg, while that of the block is M=1.06 kg. After the collision the block/bullet system swings and reaches a maximum height of h 0.85 m above its initial height. Neglect air resistance.
Part (a) Enter an expression for the speed of the block/bullet system immediately after the collision in terms of defined quantities and g. vyv(2gh) ✔Correct! Part (b) Find the speed of the block/bullet system, in meters per second, immediately after the collision. vw4:26 x Attempts Remain Part (e) Enter an expression for the initial speed of the bullet in terms of defined quantities and g. Part (d) Find the initial speed of the bullet, in meters per second. Part (e) Find the initial kinetic energy of the bullet, in joules. Part (1) Enter an expression for the kinetic energy of the block/bullet system immediately after the collision, in terms of defined quantities and g. Part (g) Calculate the ratio, expressed as a percent, of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet. KE/KE(%) = 1 sin() cotan() atan() cosh() cos() asin() tan() acos() sinh() cotanh() acotan() tanho Degrees O Radians Submit Hint 2 7 8 9 HOMIL 5 6 2 3 E14 N 1 0 VU BACKPACE . A CLEAN teation per feedback.