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A solenoid with 465 turns has a length of 6.50 cm and a cross-sectional area of 2.60 x 10-9 m². Find the solenoid's indu
Posted: Thu Jul 07, 2022 2:07 pm
by answerhappygod
- A Solenoid With 465 Turns Has A Length Of 6 50 Cm And A Cross Sectional Area Of 2 60 X 10 9 M Find The Solenoid S Indu 1 (15.42 KiB) Viewed 44 times
A solenoid with 465 turns has a length of 6.50 cm and a cross-sectional area of 2.60 x 10-9 m². Find the solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to -3.50 A in 6.83 x 10-³ s. HINT (a) the solenoid's inductance (in H) H (b) the average emf around the solenoid (in V) Need Help? Read It