When determining the hybridization for an atom that has a lone pair, one must determine whether the lone pair is capable
Posted: Thu Jul 07, 2022 2:00 pm
When determining the hybridization for an atom that has a lonepair, one must determine whether the lone pair is capable ofdelocalizing toward a neighboring atom to form a pi bond. Selectall of the statements that correctly describe the circumstancesunder which lone pair electrons can and cannot delocalize.
Group of answer choices:
A lone pair cannot delocalize if the resulting pi bond causeseither atom to violate the octet rule (for 2nd periodelements).
A lone pair will delocalize if the neighboring atom has sp3hybridization.
A lone pair can delocalize if the neighboring atom has sp2hybridization.
A lone pair will only delocalize if the neighboring atom has ahigher electronegativity value.
Lone pair electrons can delocalize if the neighboring atom hasan incomplete octet.
The lone pair on an atom will delocalize if that atom alreadyhas a pi bond.
The lone pair on an atom cannot delocalize if that atom alreadyhas a pi bond.
Lone pair electrons that cause a negative formal charge alwaysdelocalize toward the neighboring atom.
All lone pair electrons can delocalize.
Group of answer choices:
A lone pair cannot delocalize if the resulting pi bond causeseither atom to violate the octet rule (for 2nd periodelements).
A lone pair will delocalize if the neighboring atom has sp3hybridization.
A lone pair can delocalize if the neighboring atom has sp2hybridization.
A lone pair will only delocalize if the neighboring atom has ahigher electronegativity value.
Lone pair electrons can delocalize if the neighboring atom hasan incomplete octet.
The lone pair on an atom will delocalize if that atom alreadyhas a pi bond.
The lone pair on an atom cannot delocalize if that atom alreadyhas a pi bond.
Lone pair electrons that cause a negative formal charge alwaysdelocalize toward the neighboring atom.
All lone pair electrons can delocalize.