A student determines the value of the equilibrium constant to be 3.58x10-18 for the following reaction. Fe3O4(s) + 4H₂(g
Posted: Thu Jul 07, 2022 1:57 pm
A student determines the value of the equilibrium constant to be 3.58x10-18 for the following reaction. Fe3O4(s) + 4H₂(g) 3Fe(s) + 4H₂O(g) Based on this value of Keq: AG for this reaction is expected to be (greater, less) Calculate the free energy change for the reaction of 1.95 moles of Fe3O4(s) at standard conditions at 298K. kJ AG rxn = than zero.