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From the following data: C(graphite) + O2(g) → CO2(g) AHOrxn = -393.5kJ/mol H2(g) + 1/2O2(g) → H₂O(1) AHOrxn = -285.8kJ/
Posted: Thu Jul 07, 2022 1:54 pm
by answerhappygod
- From The Following Data C Graphite O2 G Co2 G Ahorxn 393 5kj Mol H2 G 1 2o2 G H O 1 Ahorxn 285 8kj 1 (33.56 KiB) Viewed 79 times
From the following data: C(graphite) + O2(g) → CO2(g) AHOrxn = -393.5kJ/mol H2(g) + 1/2O2(g) → H₂O(1) AHOrxn = -285.8kJ/mol 2C2H6(g) +702(g) → 4CO2(g) + 6H2O(l) AH°rxn = -3119.6kJ/mol Calculate the enthalpy change for the reaction: 2C(graphite) + 3H2(g) → C2₂H6(9) O a. -84.6kJ/mol O b.-3798.9kJ/mol O c. 308.9kJ/mol O d.-2520.3kJ/mol