pls help! Ka of HCNO = 3.5 x 10^-4
Posted: Thu Jul 07, 2022 1:53 pm
pls help!
Ka of HCNO = 3.5 x 10^-4
Question 5 (1 point) What is the equilibrium constant of the following reaction at 25°C? LICNO(aq) + HCl(aq) HCNO(aq) + LiCl(aq) 1) 2.9 × 10-¹1 2) 2.9 × 10³ 3) 3.4 × 10-18 4) 3.4 x 10-4 5) 2.9 × 10¹7
Ka of HCNO = 3.5 x 10^-4
Question 5 (1 point) What is the equilibrium constant of the following reaction at 25°C? LICNO(aq) + HCl(aq) HCNO(aq) + LiCl(aq) 1) 2.9 × 10-¹1 2) 2.9 × 10³ 3) 3.4 × 10-18 4) 3.4 x 10-4 5) 2.9 × 10¹7