A student determines the value of the equilibrium constant to be 4.16x105 for the following reaction. 1₂(g) + Cl₂(g) 2IC
Posted: Thu Jul 07, 2022 1:52 pm
A student determines the value of the equilibrium constant to be 4.16x105 for the following reaction. 1₂(g) + Cl₂(g) 2ICI(g) Based on this value of Keq: AG for this reaction is expected to be (greater, less) Calculate the free energy change for the reaction of 2.00 moles of 1₂(g) at standard conditions at 298K. AGºrxn= kJ than zero.