A student determines the value of the equilibrium constant to be 2.50x10-25 for the following reaction. CH4 (9) + H₂O(g)
Posted: Thu Jul 07, 2022 1:52 pm
A student determines the value of the equilibrium constant to be 2.50x10-25 for the following reaction. CH4 (9) + H₂O(g) 3H₂(g) + CO(g) Based on this value of Keq: AG for this reaction is expected to be (greater, less) than zero. Calculate the free energy change for the reaction of 1.65 moles of CH4 (9) at standard conditions at 298K. AGO, kJ rxn