enter a balanced redox equation for the resction that occurs.
Posted: Thu Jul 07, 2022 1:49 pm
enter a balanced redox equation for the resction that occurs.
MISSED THIS? Watch KCV 19.4; Read Section 19.4. You can click on the Review link to access the section in your eText. Consider the table of the standard electrode Reduction half-reaction Au³+ (aq) + 3e → Au(s) 103¯(aq) + 6H+ (aq) +5e¯ → ⁄12(aq) + 3H₂O(1) 2H+ (aq) + 2e → H₂(g) Cr³+ (aq) + 3e →→ Cr(s) potentials at 25 °C: & medlemsta le ama o MALKISANAKIN DE HEREN KALAN KAK MEN NIE E° (V) 1.50 1.20 0 -0.73
Part A Identify whether Au or Cr or both or neither will dissolve in 1 M HIO₂. Only Au will dissolve. Only Cr will dissolve. Both Au and Cr will dissolve. ONeither Au nor Cr will dissolve. O Previous Answers ✓ Correct HIO, oxidizes metals through the following reduction hall-reaction: IO (aq) + 6H (aq) +5e 12(aq) + 3H₂O(1) Because this half-reaction is above the reduction of H in the table, HIOs can oxidize some metals (for example, copper or silver) that cannot be oxidized by HCl. In general, the metals with reduction half-reactions listed below the reduction of IO, to Ia in the table dissolve in HIO3, whereas the metals listed above it do not. Therefore, Au (which has a reduction potential of 1.50 V) will not be oxidized, but Cr (which has a reduction potential of -0.73 V) will be oxidized by both HCl and HIO,.
Part B Enter a balanced redox equation for the reaction that occurs. Express your answer as a balanced net lonic equation including phases. | ΑΣΦ + 610 (aq) +36Hf(aq) + 10Cr(aq)→31, (aq) + 10Cr¹ (aq) + 13H, O(1) ? 3 A chemical reaction does not occur for this question. Check your placement of subscripts and superscripts. You can also review how to insert subscripts and more. No credit lost. Try again. Submit Previous Answers Request Answer
MISSED THIS? Watch KCV 19.4; Read Section 19.4. You can click on the Review link to access the section in your eText. Consider the table of the standard electrode Reduction half-reaction Au³+ (aq) + 3e → Au(s) 103¯(aq) + 6H+ (aq) +5e¯ → ⁄12(aq) + 3H₂O(1) 2H+ (aq) + 2e → H₂(g) Cr³+ (aq) + 3e →→ Cr(s) potentials at 25 °C: & medlemsta le ama o MALKISANAKIN DE HEREN KALAN KAK MEN NIE E° (V) 1.50 1.20 0 -0.73
Part A Identify whether Au or Cr or both or neither will dissolve in 1 M HIO₂. Only Au will dissolve. Only Cr will dissolve. Both Au and Cr will dissolve. ONeither Au nor Cr will dissolve. O Previous Answers ✓ Correct HIO, oxidizes metals through the following reduction hall-reaction: IO (aq) + 6H (aq) +5e 12(aq) + 3H₂O(1) Because this half-reaction is above the reduction of H in the table, HIOs can oxidize some metals (for example, copper or silver) that cannot be oxidized by HCl. In general, the metals with reduction half-reactions listed below the reduction of IO, to Ia in the table dissolve in HIO3, whereas the metals listed above it do not. Therefore, Au (which has a reduction potential of 1.50 V) will not be oxidized, but Cr (which has a reduction potential of -0.73 V) will be oxidized by both HCl and HIO,.
Part B Enter a balanced redox equation for the reaction that occurs. Express your answer as a balanced net lonic equation including phases. | ΑΣΦ + 610 (aq) +36Hf(aq) + 10Cr(aq)→31, (aq) + 10Cr¹ (aq) + 13H, O(1) ? 3 A chemical reaction does not occur for this question. Check your placement of subscripts and superscripts. You can also review how to insert subscripts and more. No credit lost. Try again. Submit Previous Answers Request Answer