Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3
Posted: Thu Jul 07, 2022 1:48 pm
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)₂(aq) + 2NH₂I(aq) →→→ Pbl, (s) + 2NH4NO3(aq) -> What volume of a 0.650 M NH4I solution is required to react with 327 mL of a 0.220 M Pb(NO3)2 solution? volume: How many moles of PbI2 are formed from this reaction? moles: mL mol Pbl2