Consider the reaction. 2 Pb(s) + O₂(g) -> An excess of oxygen reacts with 451.4 g of lead, forming 399.2 g of lead(II) o
Posted: Thu Jul 07, 2022 1:47 pm
Consider the reaction. 2 Pb(s) + O₂(g) -> An excess of oxygen reacts with 451.4 g of lead, forming 399.2 g of lead(II) oxide. Calculate the percent yield of the reaction. percent yield: 2 PbO(s) %