Answer Happy

QUESTION 7 When chlorobutane is treated with lithium metal, as shown below (step 1), an alkyllithium reagent A is produced. The alkyllithium reagent A (two equivalent) reacts with copper(1) iodide in diethyl ether to give a Gilman reagent G (step 2) which in turn undergoes coouping reaction with chloropropane to give product P (step 3) (Textbook problem 10-11): CH3CH₂CH₂CI 2A + Cul G+ CH₂CH₂CH₂Cl CH₂CH₂CH₂CH₂Cl 2A + Cul G CH₂CH₂CH₂Cl 2Li pentane Ether Ether 0 °C 2Li pentane Ether Ether 0 °C The name of alkyllithium reagent A is The name Gilman reagent G is The product Pis A an alkyllithium reagent G P A an alkyllithium reagent G a Gilman reagent P a Gilman reagent
Calculate the oxidation levels of each of the following compounds (Textbook problem 10-12 and worked example 10-2): CH3CH₂CH₂Cl 2A + Cul 2Li pentane Ether Ether 0 °C G + CH₂CH₂CH₂Cl CH₂CH₂CH=CHCH=CH₂ A D mond-on CH₂CH₂CH=CHCH₂C-OH A an alkyllithium reagent G P CHỊCH,CH=CHCH, CH3 B CI a Gilman reagent CH3CHCHCH₂CH₂CH CHCH₂CH₂CH The oxidation levels of compound A is The oxidation levels of compound B is The oxidation levels of compound C is The oxidation levels of compound D is The oxidation levels of compound E is The oxidation levels of compound F is The compound with lowest oxidation level is E CH₂CH₂CH₂CH₂CH₂CH3 C NH₂ CH₂CH₂CH=CHCHCH3 F
QUESTION 9 Tell whether each of the following reactions is an oxidation, a reduction, or neither (Textbook problem 10-13): O CrO₂, H₂O* CH3COH CH₂CH CH₂CH3 CH₂CH₂CH=CHCH₂ 1. CH₂MgBr, ether 2. H₂0* CH₂CH₂CH=CHCH3 VA B C OH CH₂CHCH₂ OSO4 NMO H₂ Pd/C A B OH OH CH3CH₂CH-CHCH3 CH3CH₂CH₂CH₂CH3 A. Oxidation B. Neither c. Reduction с D