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● For liquid methane at standard condition, S°(298.15K) = 126.8J mol-1.K-¹ Given that · Tb = 337.7K AvapH (337.7K) = 36.

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● For liquid methane at standard condition, S°(298.15K) = 126.8J mol-1.K-¹ Given that · Tb = 337.7K AvapH (337.7K) = 36.

Posted: Thu Jul 07, 2022 1:44 pm
by answerhappygod
For Liquid Methane At Standard Condition S 298 15k 126 8j Mol 1 K Given That Tb 337 7k Avaph 337 7k 36 1
For Liquid Methane At Standard Condition S 298 15k 126 8j Mol 1 K Given That Tb 337 7k Avaph 337 7k 36 1 (79.45 KiB) Viewed 13 times
● For liquid methane at standard condition, S°(298.15K) = 126.8J mol-1.K-¹ Given that · Tb = 337.7K AvapH (337.7K) = 36.5kJ · mol-¹ C = 81.12J. mol-¹ . K-¹ C = 43.8J. mol-¹.K-¹ -1 Tb: boiling point; I: liquid; g: gas. Find S°(298.15K) of gaseous methane.
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