Answer Happy

Question 8 The DNA of every individual in the pedigree shown in image B (below) has been sequenced at the causative locus, all the non- shaded individuals are wild type apart from II.5. II.5 has been proven to have the causative mutation for the condition but does not exhibit any of the phenotypic signs or symptoms. Based on this pedigree, what is the level of penetrance for the condition? Please give your answer as a percentage to one decimal place, give the number only, no percentage symbol. ANSWER: Given the information above I calculate the level of penetrance seen in image B to be Blank 1 percent. A KEY Homozygous Homozygous Heterozygous Heterozygous Was Type We Type Male Female Female Male Female Note: Completely red symbol denotes an individual exhibiting the phenotype of interest CL 11 111 IN V Questions Filter (28) 1/4 12 1/2 1.0. 12 1/2 1/4 1/2 B Affected Known carrier Normal Affected male 5 Points D ...