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Question Materials Genetic problems 2 coins (penny, nickel) - labelled Procedure These problems are set up to predict the results of a genetic cross between a father and mother. You are given this procedure to follow so that you can systematically solve them. 1. Write the phenotype of both parents. 2. Write the genotype of both parents. Each parent has two alleles which make up the genotype. 3. Predict the genotypes of gametes from each parent. Each gamete genotype has only one allele because it has only one set of DNA. 4. Set up the Punnett Square to predict the results of combining gametes from the parents. Combining gametes is the equivalent of fertilization when the sperm penetrates the egg. Place the sperm genotypes across the top two square and the egg genotypes on the side of the two squares. 5. Predict the genotypes of the offspring by systematically combining a gamete from the mother with a gamete from the father in the four center boxes. Now you have new hypothetical organisms, each with two alleles. Each center box represents one hypothetical offspring. 6. Predict the phenotypes of the offspring based on the genotypes above. 7. Perform a coin toss to model the chance of the parents producing particular offspring. Autosomal Dominant Disorder: Huntington's Disease t y bui La
COFFRE D heritance Lab.pdf Pipety Genotype Genotype HH Table 1: Expected Probabilities for Huntington's Disease Genotype Phenotype probability as a probability as a fraction percent Hh Q QU g. Calculate the probability of each genotype and phenotype as listed. Fill in table below on the following page. hh 58 Phenotype probability as a fraction Phenotype probability as a percent Get
Preview FR T ce Wind Help We are going to test the ratio of offspring given the parental genotypes above for Huntington's Disease by using a coin toss. The procedure is: 1. Obtain two coins. One represents the possible genotype(s) of the egg. The other HH Hh h. What are the chances a child will have Huntington's Disease? Report data as a percentage: as a fraction: Table 2. Data for Huntington's Disease Genotype Total # (Total # genotype /24) x 100 in % hh 240 2- doe represents the possible genotype(s) of the sperm. 2. Get one coin that represents the gametes of the mother. Each side of the coin represents one allele in a single gamete. Repeat for the father. 3. One student represents the mother and will flip the mother's coin. A second student represents the father and will flip the father's coin at the SAME time. 4. Note the two gametes that are face up. This represents the genotype of the offspring Tally this genotype in the table below. 5. Repeat steps 1-4 24 times. genotype after 24 tosses Probability Phenotype Total # from Punnett Square in % phenotype after 24 tosses the fe (total # phenotype /24) x 100 in % JA @D Probability from Punnett Square in % SAME THEME 7:00 P S
F E BUR View CA 22: Wim Hep 0990 Did your results from the coin tosses support your prediction from the Punnett Square? Specify the data you used. 59 Autosomal Recessive Disorder: Cystic Fibrosis 2. Cystic fibrosis is lethal autosomal recessive disorder in humans. It is the most common fatal disorder in the United States. Its hallmark is bacterial infections of the lungs and intestine. A woman who is a carrier of cystic fibrosis (Ce) has children with a man who is also a carrier (Ce). What are the chances that a particular child will have cystic fibrosis? What are the chances that a particular child will be a carrier? ЛА SAME JEG 7:00 PM
FERIE 0 heritance Lab.pdf Autosomal Recessive Disorder: Cystic Fibrosis 2. Cystic fibrosis is lethal autosomal recessive disorder in humans. It is the most common fatal disorder in the United States. Its hallmark is bacterial infections of the lungs and intestine. A woman who is a carrier of cystic fibrosis (Ce) has children with a man who is also a carrier (Ce). What are the chances that a particular child will have cystic fibrosis? What are the chances that a particular child will be a carrier? a. Phenotypes of the parents: Mother: b. Genotypes of the parents: Mother: e. Gamete genotypes: d. Punnett Square: (egg) 0QQ0 Egg: (sperm) Father: Father: Sperm A D WA 70 P Vef
SIE PLE -S BAL e. List all possible genotypes of offspring of these parents: 1. Which of these genotypes are heterozygous? 2. Which of these genotypes are homozygous? f. List all the possible phenotypes of offspring of these parents: g. Calculate the probability of each genotype and phenotype as listed. Fill in table on the following page. JA 6 60 nges the father and will A D AL
Precien heritance Lab Table 3: Expected Probabilities for Cystic Fibrosis Genotype Genotype Phenotype Genotype probability as al percent CC Cc co 20 probability as a fraction Phenotype probability as a fraction h. What are the chances a child will have cystic fibrosis? Report data as a percentage: as a fraction: i. What are the chances a child will be a carrier of cystic fibrosis? Report data as a percentage: as a fraction: We are going to test the ratio of offspring given the parental genotypes above for Cystic Fibrosis by using a coin toss. Obtain the appropriate coins for the mother and father. Follow the previous coin toss procedure. Table 4. Data for Cystic Fibrosis Genotyne Total (Total# Probability Phenotyne Total Phenotype probability as a percent (total # A Probability
wwwLagu 3 LE com tuss procedure. Table 4. Data for Cystic Fibrosis (Total # Genotype Total # genotype genotype after 24 tosses CC Ce се /24) X 100 in % 2 Probability Phenotype Total # from phenotype Punnett Square in . % after 24 tosses Did your results from the coin tosses support your prediction from the Punnett Square? Specify the data you used. Ju O (total # phenotype /24) x 100 in % 61 Probability from Punnett Square in % ♫A @D
X-Linked Recessive Disorder: Color Blindness 3. Color blindness is an X-linked recessive disorder in humans. X is a normal allele. X' is a color blind allele. A woman who is a carrier of color blindness (XX) has children with a man who is not color blind (XY). What are the chances that a male child will be colorblind! What are the chances that a child will be a carrier? a. Phenotypes of the parents: b. Genotypes of the parents: c. d. Punnett Square: Gamete genotypes: (egg) Mother: Mother: Egg: AI (sperm) pro Father: Father: Sperm : the fiche ♫A
e. List all possible genotypes of offspring of these parents 1. Which of these genotypes are heterozygous? 2. Which of these genotypes are homozygous? f. List all the possible phenotypes of offspring of these parents: g. What are the chances a boy will be colorblind? - Report data as a percentage: as a fraction: h. What are the chances that a girl will be a carrier of colorblindness? Report data as a percentage: as a fraction: 62 presents the father willip the father's SAME wwwww