HELPPP
Posted: Thu Jul 07, 2022 12:10 pm
HELPPP
Incorrect Question 3 A bored and snowbound chemist fills a balloon with 321 g water vapor, temperature 102 °C. She takes it the snowy outdoors and lets it pop, releasing the vapor, which drops in temperature to the match the outdoor temperature of -12.0 °C. What is the total energy change for the water? Give your answer with unit kJ and 3 sig figs. Heat Capacity of H₂0 as: Solid 2.05 J/(g K) Liquid 4.18 J/(g K). Vapor 2.08 J/(g K) Molar Heat of Fusion for H₂O: 6.02 kJ/mol Molar Heat of Vaporization for H₂0: 40.7 kJ/mol Tbp = 100.0 °C Tfp = 0.00 °C 0 / 2 pts 977 kJ
Incorrect Question 5 Calculate the new boiling and freezing temperatures of 4451 g water when 1.01 kg of ethylene glycol (antifreeze, C₂H60₂) is added. enter answer with correct sig figs, no unit [NOTE: watch sig figs in mixed math!] Tbp pure water = 100.0°C Kbp= 0.512 °C/m Kfp = 1.86 °C/m Molar mass of ethylene glycol = 62.07 g/mol new boiling point 102 new freezing point -6.81 Tfp pure water = 0.00 °C ос 0 / 1.5 pts ос
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Incorrect Question 5 Calculate the new boiling and freezing temperatures of 4451 g water when 1.01 kg of ethylene glycol (antifreeze, C₂H60₂) is added. enter answer with correct sig figs, no unit [NOTE: watch sig figs in mixed math!] Tbp pure water = 100.0°C Kbp= 0.512 °C/m Kfp = 1.86 °C/m Molar mass of ethylene glycol = 62.07 g/mol new boiling point 102 new freezing point -6.81 Tfp pure water = 0.00 °C ос 0 / 1.5 pts ос